arr of length nums.length + 1 with all zeros.h to keep track of the number of decrements needed so far.nums array:
a. Subtract arr[i] from h.
b. Compare the current element nums[i] with h:
nums[i] > h, update arr[i + k] with the difference nums[i] - h and set h to nums[i].nums[i] < h, return false as it's not possible to make all elements zero.
c. If i + k is beyond the array's length, return false.