diff of the same length as nums1 and nums2.diff with nums1[i] - nums2[i] for each index i.diff array.count to store the number of valid pairs.diff using index i:
a. If diff[i] is positive, increment count by the number of elements to the right of i.
b. If diff[i] is non-positive, perform a binary search to find the smallest index j such that j > i and diff[j] > -diff[i].
c. Increment count by the number of elements to the right of j.count.