Leetcode Problem 1794. Count Pairs of Equal Substrings With Minimum Difference

1794. Count Pairs of Equal Substrings With Minimum Difference

Leetcode Solutions

Minimizing j - a by Comparing Single Characters

  1. Initialize two arrays, firstOccurrence and lastOccurrence, of size 26 to store the first occurrence of each character in firstString and the last occurrence in secondString, respectively.
  2. Iterate over firstString from start to end, updating firstOccurrence with the index of the first occurrence of each character.
  3. Iterate over secondString from end to start, updating lastOccurrence with the index of the last occurrence of each character.
  4. Initialize minDifference to a large value and count to 0.
  5. Iterate over all 26 characters. For each character that appears in both strings, calculate the difference between its first occurrence in firstString and its last occurrence in secondString.
  6. If the difference is less than minDifference, update minDifference and reset count to 1.
  7. If the difference is equal to minDifference, increment count.
  8. Return count as the number of quadruples.
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Brute Force Substring Comparison

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