jobs array in non-decreasing order.workers array in non-decreasing order.minDays to 0 to keep track of the minimum number of days needed.jobs and workers arrays simultaneously.
a. For each pair (job, worker), calculate the days needed for the worker to complete the job as (job + worker - 1) // worker.
b. Update minDays to be the maximum of its current value and the days calculated in step 4a.minDays as the result.