dp of length numPeople / 2 + 1 and set dp[0] = 1.i from 1 to numPeople / 2 inclusive.
i, iterate j from 0 to i - 1 inclusive.dp[i] by adding dp[j] * dp[i - j - 1] to it, modulo 10^9 + 7.dp[numPeople / 2] as the final answer.