Leetcode Problem 1871. Jump Game VII

1871. Jump Game VII

Leetcode Solutions

BFS, Greedy O(N) Simple Solution

  1. Initialize a queue and add the starting index 0 to it.
  2. Initialize a variable farthest to 0, which will keep track of the farthest index we have checked.
  3. While the queue is not empty: a. Pop the front index from the queue. b. If this index is the last index of the string, return true. c. Calculate the range of next possible jumps based on minJump and maxJump, and update farthest. d. Iterate through the range and add valid indices (where s[i] == '0') to the queue. e. Update farthest to the maximum of its current value and the right boundary of the current range.
  4. If the loop ends without reaching the last index, return false.
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