dp to store the maximum length of an arithmetic subsequence ending with each element.answer to 1, which is the minimum length of any subsequence.arr[i] in the array.before_a as the length of the longest subsequence ending with arr[i] - difference.
arr[i] - difference is in dp, before_a = dp[arr[i] - difference].before_a = 0.dp[arr[i]] to before_a + 1.answer to the maximum of answer and dp[arr[i]].answer.