Leetcode Problem 2499. Minimum Total Cost to Make Arrays Unequal

2499. Minimum Total Cost to Make Arrays Unequal

Leetcode Solutions

Greedy Approach with Frequency Counting

  1. Check if it is possible to satisfy the condition by comparing the frequency of each value in both arrays.
  2. Count the number of bad indices where nums1[i] == nums2[i] and calculate their sum.
  3. Find the value with the highest frequency among the bad indices.
  4. Determine the number of pairs that can be formed by swapping bad indices with each other.
  5. If there are remaining bad indices, find the lowest index that can be swapped with a bad index.
  6. Calculate the total cost by adding the index of each swap to the initial sum of bad indices.
  7. Return the total cost if the condition can be satisfied, otherwise return -1.
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Brute Force with Optimization

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