ans of size n to store the result for each node.dfs that takes the current node and its parent as arguments.dfs, initialize a 26-length array count to keep track of the label counts in the subtree.count[labels[node] - 'a'] to 1 since the node itself should be counted.dfs on the child.count array.ans[node] to the count of the node's label.count array from the dfs function.dfs starting from the root node (0) with no parent (-1).ans array.