dp with dimensions [m][n][k] and fill it with zeros.dp[0][0][grid[0][0] % k] to 1, as there is one path to the starting cell with the remainder of the first cell's value modulo k.(i, j), iterate over all possible remainders r from 0 to k-1.(i-1, j) and the cell to the left (i, j-1) that have a remainder r when their path sums are divided by k.dp[i][j][(grid[i][j] + r) % k] with the sum of these paths, modulo 10^9 + 7 to prevent integer overflow.dp array, return the value of dp[m-1][n-1][0], which represents the number of paths that reach the bottom-right corner with a sum divisible by k.