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Leetcode Problem 2423. Remove Letter To Equalize Frequency

2423. Remove Letter To Equalize Frequency

Leetcode Solutions

Frequency Counting and Condition Checking

  1. Initialize an array counts of size 26 to keep the frequency of each letter in the word.
  2. Maintain a variable distinct to count the number of distinct letters.
  3. Iterate through the word, updating counts for each letter and incrementing distinct when a letter is first encountered.
  4. Sort the counts array.
  5. Check the following conditions:
    • If there's only one distinct letter, return true.
    • If the highest frequency is one, return true.
    • If the highest frequency can be decreased by one to match the second-highest and all other frequencies are equal, return true.
    • If the least frequent letter can be removed and the most frequent letter has the same frequency as all others when the least frequent is discounted, return true.
  6. If none of the conditions are met, return false.
UML Thumbnail

Brute Force Removal and Frequency Check

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