Leetcode Problem 870. Advantage Shuffle

870. Advantage Shuffle

Leetcode Solutions

Greedy Approach to Maximize Advantage

  1. Sort nums1 and create a sorted copy of nums2.
  2. Initialize a dictionary assigned to store the elements of nums1 that can beat elements of nums2.
  3. Initialize a list remaining to store the elements of nums1 that cannot beat any element in nums2.
  4. Use two pointers, one for nums1 and one for the sorted nums2, to iterate through both arrays.
  5. For each element in sorted nums2, if the current element in nums1 can beat it, assign it to assigned and move both pointers. Otherwise, add the element in nums1 to remaining and move only the pointer for nums1.
  6. After iterating through both arrays, use assigned and remaining to reconstruct the final answer array.
  7. For each element in the original nums2, if there is an assigned element in assigned, use it. Otherwise, use the next element from remaining.
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Brute Force Approach with Sorting

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