Leetcode Problem 1067. Digit Count in Range

1067. Digit Count in Range

Leetcode Solutions

Digit Counting by Position

  1. Define a helper function getCounts that takes an integer num and returns the count of digit d up to num.
  2. In getCounts, initialize res (result) to 0, step to 1 (representing the current digit position), and n to 0 (representing the number formed by digits to the right of the current position).
  3. Loop while num is greater than 0: a. Calculate the current digit t as num % 10. b. Update num to num // 10. c. Depending on the value of t relative to d, update res accordingly. d. Update n to include the current digit and step to move to the next digit position.
  4. Return res.
  5. The main function digitsCount calls getCounts(high) - getCounts(low - 1) to get the final count of digit d in the range [low, high].
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Brute Force Digit Counting

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