Leetcode Problem 72. Edit Distance

72. Edit Distance

Leetcode Solutions

Bottom-Up Dynamic Programming: Tabulation

  1. Initialize a 2D array dp with dimensions (len(word1) + 1) x (len(word2) + 1).
  2. Fill the first row of dp with indices 0 to len(word2), representing the operations needed to convert an empty word1 to word2.
  3. Fill the first column of dp with indices 0 to len(word1), representing the operations needed to convert word1 to an empty word2.
  4. Iterate over the characters of word1 and word2 using two nested loops.
  5. For each pair (i, j), check if word1[i - 1] is equal to word2[j - 1].
  6. If they are equal, set dp[i][j] to dp[i - 1][j - 1].
  7. If they are not equal, set dp[i][j] to the minimum of dp[i - 1][j], dp[i][j - 1], and dp[i - 1][j - 1] plus 1.
  8. The value at dp[len(word1)][len(word2)] is the minimum number of operations required.
UML Thumbnail

Recursion

Ask Question

Programming Language
image/screenshot of info(optional)
Full Screen
Loading...

Suggested Answer

Answer
Full Screen
Copy Answer Code
Loading...