left to 0 and right to len(arr) - k.left < right:
a. Calculate mid as (left + right) // 2.
b. Compare arr[mid] and arr[mid + k] to x.
c. If arr[mid] is closer to x, move right to mid.
d. Otherwise, move left to mid + 1.left will be at the start of the k closest elements.left to left + k.