findKthBit that takes n and k as arguments.n is 1, return '0' as S1 is always '0'.Sn which is 2^n - 1.Sn which is length / 2 + 1.k is equal to the middle index, return '1'.k is less than the middle index, recursively call findKthBit with n-1 and k.k is greater than the middle index, recursively call findKthBit with n-1 and length - k + 1 to find the corresponding bit in the reversed and inverted Sn-1, and then invert the result before returning it.