ans, s0, and s1 to 1, representing the length of the longest non-decreasing subarray found so far, and the lengths of the subarrays ending at the previous index for nums1 and nums2, respectively.n - 1.i, update s0 and s1 as follows:
s0 becomes the maximum of s0 (if nums1[i-1] <= nums1[i]) and s1 (if nums2[i-1] <= nums1[i]) plus 1.s1 becomes the maximum of s0 (if nums1[i-1] <= nums2[i]) and s1 (if nums2[i-1] <= nums2[i]) plus 1.ans with the maximum of ans, s0, and s1.ans as the result.