Leetcode Problem 2531. Make Number of Distinct Characters Equal

2531. Make Number of Distinct Characters Equal

Leetcode Solutions

Frequency Map and Unique Character Count Comparison

  1. Initialize two frequency maps (arrays) for word1 and word2 to count character occurrences.
  2. Count the number of unique characters in both words.
  3. If the number of unique characters is equal and the lengths of both words are equal, return true.
  4. Iterate through each character in word1 and word2.
  5. For each pair of characters, simulate a swap by adjusting the frequency maps accordingly.
  6. After the simulated swap, count the new number of unique characters in both words.
  7. If the number of unique characters is equal, return true.
  8. Revert the changes to the frequency maps to simulate the next swap.
  9. If no swap results in an equal number of unique characters, return false.
UML Thumbnail

Set Operations to Determine Potential Swaps

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