Leetcode Problem 2008. Maximum Earnings From Taxi

2008. Maximum Earnings From Taxi

Leetcode Solutions

Dynamic Programming with Ride Start Point Optimization

  1. Create a list rideStartAt to store rides starting from each point.
  2. Populate rideStartAt with the rides, where each ride is represented as a pair of its end point and the total earnings from that ride.
  3. Initialize a DP array dp of size n + 1 with all elements set to 0.
  4. Iterate over the points in reverse order, from n - 1 to 1.
  5. For each point i, iterate over all rides starting from that point.
  6. For each ride starting at point i, calculate the potential earnings and update dp[i] if the potential earnings are higher than the current value of dp[i].
  7. After considering all rides starting at point i, update dp[i] to be the maximum of its current value and dp[i + 1].
  8. The answer to the problem is the value of dp[1], which represents the maximum earnings starting from point 1.
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Recursive Approach with Memoization and Binary Search

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