Leetcode Problem 1614. Maximum Nesting Depth of the Parentheses

1614. Maximum Nesting Depth of the Parentheses

Leetcode Solutions

Iterative Stack Depth Counting

  1. Initialize two integer variables, currentDepth and maxDepth, to 0.
  2. Iterate through each character in the string s.
  3. If the current character is an opening parenthesis '(', increment currentDepth.
  4. If the current character is a closing parenthesis ')', decrement currentDepth.
  5. After each increment, update maxDepth to be the maximum of maxDepth and currentDepth.
  6. Continue this process until the end of the string.
  7. Return maxDepth as the result, which represents the maximum nesting depth of the parentheses in the string.
UML Thumbnail

Using Stack to Track Parentheses

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