possible(D) that returns True if we can add k or fewer gas stations such that the maximum distance between adjacent gas stations is at most D.X between stations, calculate the number of gas stations needed as math.floor(X / D).k, return True; otherwise, return False.low and high for the binary search. low can be 0, and high can be the maximum interval between existing gas stations.low is less than high:
a. Calculate mid as (low + high) / 2.
b. If possible(mid) is True, update high to mid.
c. If possible(mid) is False, update low to mid + 1e-6 (to maintain the precision requirement).low as the smallest possible value of penalty().