Leetcode Problem 2856. Minimum Array Length After Pair Removals

2856. Minimum Array Length After Pair Removals

Leetcode Solutions

Counting Maximum Occurrences and Comparing with Remaining Elements

  1. Initialize a variable max_count to store the maximum frequency of any element in the array.
  2. Iterate through the array, counting the frequency of each element and updating max_count accordingly.
  3. Calculate the number of distinct elements as distinct_count = len(nums) - max_count.
  4. If distinct_count is greater than or equal to max_count, the result is 0 if the array length is even, or 1 if the array length is odd.
  5. If distinct_count is less than max_count, the result is max_count - distinct_count.
  6. Return the result.
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Two Pointer Approach by Splitting Array

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