cuts and add 0 and n to the beginning and end of the array respectively.dp of size (m+2) x (m+2) with all elements set to 0, where m is the number of cuts.l from 2 to m+1 (inclusive).l, iterate over all possible starting points i for the subproblem.j of the subproblem to i + l.dp[i][j] to infinity.k for the next cut between i and j.dp[i][j] to the minimum of its current value and the sum of dp[i][k], dp[k][j], and the cost of making the cut at position k.dp table, return dp[0][m+1] as the answer.