Leetcode Problem 2052. Minimum Cost to Separate Sentence Into Rows

2052. Minimum Cost to Separate Sentence Into Rows

Leetcode Solutions

Dynamic Programming Approach

  1. Split the sentence into words.
  2. Initialize a DP array dp with size n+1, where n is the number of words, and set all values to infinity except dp[0] which is set to 0.
  3. Iterate over each word in the sentence from the first to the last.
  4. For each word, iterate backwards to find all possible ways to fit the word into rows.
  5. Calculate the cost of starting a new row with the current word and the cost of adding the word to an existing row.
  6. Update the dp array with the minimum cost found for arranging words up to the current word.
  7. After filling the dp array, iterate backwards from the second last word to find the minimum cost excluding the last row.
  8. Return the minimum cost found.
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