Leetcode Problem 625. Minimum Factorization

625. Minimum Factorization

Leetcode Solutions

Approach # Using Factorization

  1. If num is 1, return 1 since the product of the digits of 1 is 1.
  2. Initialize an empty list factors to store the factors of num.
  3. Loop from 9 to 2 and check if num is divisible by the current number.
  4. While num is divisible by the current number, append the current number to factors and divide num by the current number.
  5. If num is greater than 1 after the loop, return 0 since num has a prime factor greater than 9, which cannot be a digit.
  6. Sort factors in ascending order and concatenate them into a string.
  7. Convert the string to an integer.
  8. If the integer is greater than the maximum 32-bit signed integer value, return 0.
  9. Otherwise, return the integer.
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Approach # Better Brute Force

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