Leetcode Problem 2009. Minimum Number of Operations to Make Array Continuous

2009. Minimum Number of Operations to Make Array Continuous

Leetcode Solutions

Sliding Window Approach

  1. Remove duplicates from the input array and sort it.
  2. Initialize the answer to the length of the original array.
  3. Initialize a pointer j to 0.
  4. Iterate over the sorted array with index i:
    • Calculate the maximum value right as nums[i] + n - 1.
    • Increment j while nums[j] is less than or equal to right.
    • Calculate the number of elements within the range as j - i.
    • Update the answer with the minimum of the current answer and n - (j - i).
  5. Return the answer.
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Binary Search Approach

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