Leetcode Problem 1986. Minimum Number of Work Sessions to Finish the Tasks

1986. Minimum Number of Work Sessions to Finish the Tasks

Leetcode Solutions

Dynamic Programming on Subsets

  1. Define dp(mask) where mask is a bitmask representing the set of tasks that have been completed.
  2. If mask is 0 (no tasks completed), return (1, 0) indicating one session is needed with 0 time spent.
  3. For each task j that is not completed in mask: a. Calculate the result of completing task j by calling dp(mask - (1 << j)). b. Determine if adding task j to the current session would exceed the session time, requiring a new session. c. Update the minimum number of sessions and remaining time accordingly.
  4. Use memoization to store and reuse the results of dp(mask) to avoid redundant calculations.
  5. The final answer is dp((1<<n) - 1)[0], which represents completing all tasks.
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Backtracking with Greedy Session Utilization

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