total_operations to 0, which will store the total minimum operations needed.max_doublings to 0, which will store the maximum number of doubling operations needed for any number in nums.nums:
a. For the current number, initialize doublings to 0.
b. While the current number is greater than 0:
i. If the current number is odd, increment total_operations (for the increment operation) and decrement the number by 1.
ii. Right shift the current number by 1 (divide by 2), and increment doublings.
c. Update max_doublings to be the maximum of itself and doublings.max_doublings to total_operations (for the doubling operations).total_operations as the result.