Leetcode Problem 2612. Minimum Reverse Operations

2612. Minimum Reverse Operations

Leetcode Solutions

BFS with Even/Odd Parity Optimization

  1. Initialize an array ans of length n with all elements set to -1 to store the minimum number of operations required to move the 1 to each position.
  2. Create a queue for BFS and enqueue the initial position p with a count of 0 operations.
  3. While the queue is not empty, dequeue an element (current_position, operations).
  4. Calculate the range of indices that can be reached from current_position by reversing a subarray of size k.
  5. For each index in the calculated range, check if it has the same parity as current_position and is not banned.
  6. If the index is valid, update ans[index] with operations + 1 if it is not already visited, and enqueue (index, operations + 1).
  7. Continue the BFS until all reachable positions have been visited.
  8. Return the ans array.
UML Thumbnail

Simple BFS with Parity and Range Calculation

Ask Question

Programming Language
image/screenshot of info(optional)
Full Screen
Loading...

Suggested Answer

Answer
Full Screen
Copy Answer Code
Loading...