Leetcode Problem 2067. Number of Equal Count Substrings

2067. Number of Equal Count Substrings

Leetcode Solutions

Sliding Window with Fixed Unique Characters

  1. Initialize res to 0 to store the result (number of equal count substrings).
  2. Determine the maximum number of unique characters in the string s and store it in max_unique.
  3. Iterate over the number of unique characters unique from 1 to max_unique.
  4. For each unique, calculate the window size len as count * unique.
  5. Initialize a frequency array cnt to store the count of each character within the window.
  6. Initialize has_count to 0 to store the number of characters that have exactly count occurrences in the window.
  7. Use a sliding window to iterate over the string s.
  8. Increase the count of the current character in cnt and update has_count accordingly.
  9. If the window size exceeds len, decrease the count of the character at the start of the window and update has_count.
  10. If has_count equals unique, increment res.
  11. Return res as the final result.
UML Thumbnail

Brute Force with Frequency Count

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