Leetcode Problem 1473. Paint House III

1473. Paint House III

Leetcode Solutions

Approach: Bottom-Up Dynamic Programming (Space Optimized)

  1. Initialize a 2D array prevMemo to store the base case results for the first house.
  2. Iterate over the house index house from 1 to m - 1: a. Create a new 2D array memo to store the results for the current house. b. For each neighborhoods count and color, calculate the minimum cost to paint the current house. c. If the house is already painted with a different color, skip the iteration. d. Otherwise, find the minimum cost by comparing the cost of painting the current house with the previous house's cost for different scenarios. e. Update prevMemo with the results from memo.
  3. After iterating through all houses, find the minimum cost to paint the last house with target neighborhoods.
  4. Return the minimum cost or -1 if it's not possible to form target neighborhoods.
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Approach: Top-Down Dynamic Programming

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