dp with size n+1 and fill it with infinity (INF), where n is the length of the string s. Set dp[0] to 0 as the base case.s using index i.s[i] is '0', skip to the next iteration.num to 0 to store the numeric value of the current substring.i to the end using index j.num by shifting its bits to the left and adding the current character's value.num exceeds a certain limit, break the loop to avoid overflow.num is a power of 5 using a helper function isPowerOfFive.dp[j+1] with the minimum of its current value and dp[i]+1.dp[n] is still INF. If it is, return -1, indicating that it's impossible to partition the string into beautiful substrings. Otherwise, return dp[n].