dp with dimensions [n][n][n] where n is the length of the boxes array.calculatePoints(l, r, k) that returns the maximum points for the subarray boxes[l:r] with k additional elements similar to boxes[r] following it.dp[l][r][k] is already computed, return it to avoid redundant calculations.dp[l][r][k] with the value obtained by removing the last k+1 similar elements.boxes[l:r] to find elements similar to boxes[r].i, calculate the potential points by combining it with the trailing similar elements and update dp[l][r][k] if it leads to a higher score.dp[0][n-1][0] as the final result, which represents the maximum points for the entire array with no additional similar elements at the end.