n to servings m by dividing by 25 and rounding up.dp with dimensions (m+1) x (m+1).dp[0][j] = 1 for all j > 0, dp[i][0] = 0 for all i > 0, and dp[0][0] = 0.5.dp[1][1] to dp[m][m].dp[i][j], calculate its value based on the recurrence relation using the values from the previous operations.dp[k][k] is greater than 1 - 10^-5, return 1 as the answer.dp[m][m] as the final answer.