Leetcode Problem 2380. Time Needed to Rearrange a Binary String

2380. Time Needed to Rearrange a Binary String

Leetcode Solutions

Counting Zeros and Waiting Time

  1. Initialize waitingTime and zeroCount to 0.
  2. Find the last occurrence of '1' in the string and store its index in lastOcc.
  3. Iterate through the string up to lastOcc. a. If two consecutive '1's are found, increase waitingTime by 1 (if there are zeros to the left). b. If two consecutive '0's are found, decrease waitingTime by 1 (if there is a waiting time). c. If a '0' is found, increment zeroCount.
  4. The total time required is the sum of zeroCount and waitingTime.
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Brute Force Simulation

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